Math, asked by adepusushma93, 4 months ago

Solve the equation
 {x}^{4}  -  {10x}^{3}  +  {35x}^{2}  -  {50x} + 24 = 0
Given that roots are a+1,a-1,b+1,b-1​

Answers

Answered by singhsaanjhdev
0

Answer:

x

4

+10x

3

+35x

2

+50x+24.

Step-by-step explanation:

x

4

+10x

3

+35x

2

+50x+24=x

4

+(x

3

+9x

3

)+(9x

2

+26x

2

)+(26x+24x)+24

=(x

4

+x

3

)+(9x

3

+9x

2

)+(26x

2

+26x)+(24x+24)

=x

3

(x+1)+9x

2

(x+1)+26x(x+1)+24(x+1)

=(x+1)(x

3

+9x

2

+26x+24)

=(x+1)(x

3

+(2x

2

+7x

2

)+(14x+12x)+24)

=(x+1)((x

3

+2x

2

)+(7x

2

+14x)+(12x+24))

=(x+1)(x

2

(x+2)+7x(x+2)+12(x+2))

=(x+1)(x+2)(x

2

+7x+12)

=(x+1)(x+2)(x

2

+3x+4x+12)

=(x+1)(x+2)(x(x+3)+4(x+3))

=(x+1)(x+2)(x+3)(x+4)

Answered by Anonymous
2

Answer:

x^4 – 10x^3 + 35x^2– 50x + 24 = 0

Factor:

(x - 1) (x^3 - 9x^2 +26x - 24)

(x - 1) (x - 2) (x^2 - 7x + 12)

(x - 1) (x - 2) (x - 3 )(x - 4)

Answer is x = 1, 2, 3, or 4

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