Question

hehehehe bhai tu hi krega thevirat ❤️✌️❤️✌️
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Answer 1

Answer:

behenji hume bhi ye sums ate hai.

Answer 2

Given :

• Sum of zeroes of the polynomial : x² - (k+3)x + (5k - 3) is equal to one fourth of product of the zeroes.

To Find :

• The value of k.

Solution :

The given polynomial is :

• x² - (k+3)x + (5k-3)

Compare the polynomial with the general form of quadratic polynomial, ax² + bx + c.

•°• We get

• a = 1
• b = -k-3
• c = 5k-3

Sum of zeroes :

We know that the sum of zeroes is the ratio of x/x²

$\sf{Sum\:of\:zeroes\:=\:\dfrac{-b}{a}}$

$\implies$ $\sf{Sum\:of\:zeroes\:=\:\dfrac{-(-k-3)}{1}}$

$\implies$ $\sf{Sum\:of\:zeroes\:=\:\dfrac{k+3}{1}}$

$\large{\boxed{\sf{\purple{Sum\:of\:zeroes\:=\:(k+3)}}}}$

Product of zeroes :

We know that, the product of zeroes is the ratio of constant and x.

$\sf{Product\:of\:zeroes\:=\:\dfrac{c}{a}}$

$\implies$ $\sf{Product\:of\:zeroes\:=\:\dfrac{(5k-3)}{1}}$

$\large{\boxed{\sf{\red{Product\:of\:zeroes\:=\:5k-3}}}}$

Now, further given, sum of the zeroes is equal to one fourth of the product of zeroes.

$\sf{Sum\:of\:zeroes\:=\:\dfrac{1}{4}\:\times\:Product\:of\:zeroes}$

$\implies$ $\sf{k+3=\dfrac{1}{4}\:\times\:(5k-3)}$

$\implies$ $\sf{4(k+3)=5k-3}$

$\implies$ $\sf{4k+12=5k-3}$

$\implies$ $\sf{4k-5k=-3-12}$

$\implies$ $\sf{-k=-15}$

$\implies$ $\sf{k=15}$

$\large{\boxed{\sf{\red{Value\:of\:k\:=\:15}}}}$