height of a triangle are 10 cm 24 cm and 26 cm find its area
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Method 1: Using the formula
A=s(s−a)(s−b)(s−c)−−−−−−−−−−−−−−−−−−√A=s(s−a)(s−b)(s−c)
where, A: Area of the triangle, s: semi-perimeter of triangle,(a,b,c) are the sides of the triangle.
10cm,24cm,26cm10cm,24cm,26cm
Now, s=a+b+c2=10+24+262=30s=a+b+c2=10+24+262=30
A=s(s−a)(s−b)(s−c)−−−−−−−−−−−−−−−−−−√A=s(s−a)(s−b)(s−c)
⇒A=30(30−10)(30−24)(30−26)−−−−−−−−−−−−−−−−−−−−−−−−−√⇒A=30(30−10)(30−24)(30−26)
⇒A=30(20)(6)(4)−−−−−−−−−−−√=36×4×100−−−−−−−−−−√=6×2×10=120⇒A=30(20)(6)(4)=36×4×100=6×2×10=120
A=120sq.cmA=120sq.cm
Method 2: By looking the sides, we can say they form a right angle triangle.
Since, 242+102=262242+102=262
A=12∗base∗heightA=12∗base∗height
A=12×24×10=120sq.cm
A=s(s−a)(s−b)(s−c)−−−−−−−−−−−−−−−−−−√A=s(s−a)(s−b)(s−c)
where, A: Area of the triangle, s: semi-perimeter of triangle,(a,b,c) are the sides of the triangle.
10cm,24cm,26cm10cm,24cm,26cm
Now, s=a+b+c2=10+24+262=30s=a+b+c2=10+24+262=30
A=s(s−a)(s−b)(s−c)−−−−−−−−−−−−−−−−−−√A=s(s−a)(s−b)(s−c)
⇒A=30(30−10)(30−24)(30−26)−−−−−−−−−−−−−−−−−−−−−−−−−√⇒A=30(30−10)(30−24)(30−26)
⇒A=30(20)(6)(4)−−−−−−−−−−−√=36×4×100−−−−−−−−−−√=6×2×10=120⇒A=30(20)(6)(4)=36×4×100=6×2×10=120
A=120sq.cmA=120sq.cm
Method 2: By looking the sides, we can say they form a right angle triangle.
Since, 242+102=262242+102=262
A=12∗base∗heightA=12∗base∗height
A=12×24×10=120sq.cm
Answered by
0
Hay here is your answer
10 into 24 into 26
6240
10 into 24 into 26
6240
aJodedara:
answer in cm^2 you Chang into meter^2
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