Height of water dam in hydroelectric power station is 20 m. How much water, in 1 second, should fall on turbine, so that 1 MW power is generated ? (g = 10m/s2) (A) 5000 kg (B) 10,000 kg (C) 500 kg (D) 7,500 kg
GSEB - Class 9 Chapter - 1. Work, Energy and Power Page 10
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h = 20m
Power = 1Mw or 1000000 Joules
mgh = 1000000
m×10×20 = 1000000
m = 1000000/200
m = 10000/2
m = 5000 Kg
Answered by
2
Answer:
(A) 5000 kg
Explanation:
Power = P = 1MW = 1000000W (Given)
Height of water dam = h = 20m (Given)
g = 10 m/s² (Given)
Time = t= 1s (Given)
According to the equation -
P=W/t
W = mgh
= m×10×20
W= 200m
Thus,
1000000 = 200/1
m = 1000000/200
M = 5000
Therefore, 5000kgs of water should fall.
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