Question

Heisenberg's uncertainty principle

Answer 1

::::::::::HEISENBERG'S UNCERTAINTY PRINCIPAL:::::::::::
it is impossible to determine simultaneously, the exact positions and exact momentum of an electron.

Answer 2

Hey !!

Heisenberg in 1927, pointed out that it is not possible to measure both position and momentum (or velocity) of a microscope particle at the same time with absolute accuracy.

Mathematically,        Δx × Δp = h/4π

Here,                  Δx = uncertainty in position

                           Δp = uncertainty in momentum

Now,  

          p = mv

Hence,      Δp = mΔv

By putting the value of Δp in the above expression, we get

        mΔv × Δ x ≥ h/4π  (or) Δv × Δx ≥ h/4π × m

Good luck !!