Question

Helen plays basketball, for free throws, she makes the shot 75% of the time. Helen must now attempt two free throws. The probability that Helen makes the first shot is 0.75 . The probability that Helen makes the second shot is 0.75 . The probability that Helen makes the second free throw given that she made the first is 0.85. what is the probability that Helen makes both free throws?​

Answer 1

0.75+0.75+0.85 = 2.35

Answer 2

Given:

Percentage of time, Helen makes the shot = 75%

Probability that Helen makes the first shot P(A) = 0.75

Probability that Helen makes the second shot P(B) = 0.75

Probability that Helen makes the second free throw given that she made the first = 0.85

To find:

The probability that Helen makes both free throws.

Solution:

Given P(B|A) = 0.85

We know that by Multiplication rule: P(B|A) = P(A∩B)/ P(A)

Therefore P(A∩B) = P(B|A) P(A)

= 0.85 * 0.75

= 0.6375

Therefore the required probability is 0.6375.