Helen plays basketball, for free throws, she makes the shot 75% of the time. Helen must now attempt two free throws. The probability that Helen makes the first shot is 0.75 . The probability that Helen makes the second shot is 0.75 . The probability that Helen makes the second free throw given that she made the first is 0.85. what is the probability that Helen makes both free throws?
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0.75+0.75+0.85 = 2.35
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Given:
Percentage of time, Helen makes the shot = 75%
Probability that Helen makes the first shot P(A) = 0.75
Probability that Helen makes the second shot P(B) = 0.75
Probability that Helen makes the second free throw given that she made the first = 0.85
To find:
The probability that Helen makes both free throws.
Solution:
Given P(B|A) = 0.85
We know that by Multiplication rule: P(B|A) = P(A∩B)/ P(A)
Therefore P(A∩B) = P(B|A) P(A)
= 0.85 * 0.75
= 0.6375
Therefore the required probability is 0.6375.
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