hellllllllllllllllllllllllllllppppppppppppppp
Attachments:
Answers
Answered by
1
The solution of the following question is given in the picture attached below -:
Attachments:
rachudadhwal07:
Sorry
It wasn't meant for this question
I'm sorry
This answer isn't of this question
I was answering other question
ok i found it
Answered by
1
a3+b3+c3-3abc=(a+b+c)(a2+b2+c2-ab-bc-ca)
=(a+b+c)×0 (given)
=0
here (a+b+c)(a2+b2+c2-ab-bc-ca)=0
so (a+b+c)=0
hence a=0
b=0
c=0
therfore all are equal so a=b=c
hence proved
=(a+b+c)×0 (given)
=0
here (a+b+c)(a2+b2+c2-ab-bc-ca)=0
so (a+b+c)=0
hence a=0
b=0
c=0
therfore all are equal so a=b=c
hence proved
you want this answer na
yes
Similar questions