Hello Brainlians!!
Here is a question to check out your physics. Quality and correct answer needed. Please help :-
1.) A body starts with an initial velocity of 10 m/sec and acceleration 5 m/sec². Find distance covered by it in 5 seconds.
2.) An object moving along a straight line is initially moving at a velocity of +12 m/sec but is accelerating so that at a time 4 seconds later it is moving at the same speed, but in the opposite direction.
What is the object's average acceleration during the 4 seconds ?
Please answer only if you know. No spam allowed, don't be greedy for the points please. Spammers stay Away
Answers
Answered by
1
Answer:
1st answer hai above attachment Mai dekh liyo poteji
Explanation:
2. Initial velocity of the object v
i
=+12 m/s (positive direction)
Final velocity of the object v
f
=−12 m/s (negative direction)
Thus acceleration of the object a=
t
v
f
−v
i
=
4
−12−12
=−6 m/s
2
Attachments:
![](https://hi-static.z-dn.net/files/dcf/37fc6c23433bdf1ceeccdbfae9786da1.jpg)
Similar questions