Question

✴ Hello! Brainly ki Public ❤

✏ Kamal and Anand each lent the same sum of money for 2 years at 5% at simple interest respectively.
Anand received ₹15 more than Kamal .
Find the amount of money lent by each and the interest received .

✳Full solution needed✅

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Answer 1

Hello mate,

Here is your answer,

Given:

• Time (T) = 2 years

• Rate of interest (R) = 5%

• Anand received ₹15 more than Kamal

To Find:

• Amount of money lent by each person and the interest received.

Solution:

For Kamal,

T = 2 years

R = 5%

We know,

$simple \: \: interest = \frac{ptr}{100}$

Substituting the values,

$s.i = \frac{10p}{100} \\ \\ = 0.1p \: \: \: \: \: ....(1)$

For Anand,

T = 2 years

R = 5%

Amount = $p( {1 + \frac{r}{100}) }^{t}$

Substituting the values,

$a = p( {1 + \frac{5}{100} )}^{2} \\ \\ = p( {1.05)}^{2} \\ \\ = 1.1025p \: \: \: \: \: ....(2)$

We know compound interest = (Amount) - (Principle)

C.I = (1.1025)p - (p)

= (0.1025)p

Anand got ₹15 more than Kamal, so,

C.I - S.I = 15

(0.1025) p - (0.1) p = 15

(0.0025) p = 15

• p = ₹6000

Now,

the simple interest received by Kamal = (0.1)p

Substitute principle value,

= (0.1) (6000)

= ₹600

Compound interest received by Anand = (0.1025)p

Substitute principle value,

(0.1025)(6000)

= ₹615

Hope it helps:)

Answer 2

Answer:

Let the principal amount be P

Interest received by Kamal is=

SI = PRT/100

SI = P(5)(2)/100

SI = P/10 = 0.1P

Interest received by Anand is =

CI = P [ (1 + r/100)^t - 1 ]

CI = P [ (1 + 5/100)² - 1 ]

CI = P [ (1.05)² - 1 ]

CI = P [ 0.1025 ] = 0.1025 P

As difference between their interests is 15 we get

CI - SI = 15

Putting values, we get

0.1025P - 0.1P = 15

0.0025P = 15

25/10000 P = 15

P = 6000

So, SI = 0.1P = 6000(0.1) = 600

And CI = 600 + 15 = 615

Therefore, Kamal received 600 interest, Anand received 615; both on principal of 6000