Question

in figure angle R PQ = 90 degree S is the midpoint of Q R and S P = 2.5 CM compute the area of triangle pqr​

Answer 1

Answer:

The area of triangle of PQR is 6 square cm.

Step-by-step explanation:

Concept:

The midpoint of the hypotenuse of a right angled triangle is equidistant from its vertices.

Then,

PS=QS=RS=2.5 cm

and QR=5 cm

By pythagoras theorem, we get

$PQ^2+PR^2=QR^2$

$PQ^2+(3)^2=(5)^2$

$PQ^2+9=25$

$PQ^2=25-9$

$PQ^2=16$

$PQ=4\,cm$

Now,

Area of triangle PQR

$=\frac{1}{2}*base*height$

$=\frac{1}{2}*PQ*PR$

$=\frac{1}{2}*4*3$

$=6\,square\,cm$