Question

✯hello brainly users ✯

question :-
☞ A tree is broken at a height of 5m from the ground and it's top touches the ground at a distance of 12m from the base of the tree. Find the original height of the tree? solve it with figure ​

Answer 1

Let A'CB represents the tree before it broken at the point C and let the top A' touches the ground at A after it broke. Then ΔABC is a right angled triangle, right angled at B.

AB=12m and BC=5m

Using Pythagoras theorem, In ΔABC

(AC)^2 + (AB)^2 + (BC)^2

=> (AC)^2 = (12)^2 + (5)^2

=> (AC)^2 = 144 + 25

=> (AC)^2 = 169

=> AC = 13m

Hence, the total height of the tree=AC+CB=13+5=18m.

hope it helps you :-)