Question

Hello can u all plz solve this for me

Plz^ 1000000000000000000

But with complete solution!

Answer 1

$Given : 4^{x - 1} * (0.5)^{3 - 2x} = ( \frac{1}{8})^x$

$(2^2)^{x - 1} * (\frac{1}{2}) ^{3 - 2x} = ( \frac{1}{8} )^x$

$2^2^{ (x - 1)} * 2^{-1(3 - 2x)} = ( \frac{1}{2^3} )^x$

$2^{2(x - 1)} * 2^{-1(3 - 2x)} = 2^{-3x}$

$2^2^{(x - 1) - 1(3 - 2x) } = 2^{-3x}$

2(x - 1) - 1(3 - 2x) = -3x

2x - 2 - 3 + 2x = -3x

4x - 5 = -3x

7x = 5

x = 5/7.


Hope this helps!

Answer 2

Hi,

Please see the attached file!


Thanks