Question

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Answer my questions which are given in the attachment

❤Conditions=> Fullexplanation❤

Class => 11

Subject => Physics

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Jai bajarang bali

@Dr. S.M.

Answer 1

Heya mate   ●●For block of mass 10kg, acceleration will be downward, ☆Weight - Tension = ma ●mg - T = ma ●10g - T = 10a ------ 1 ☆☆Similarly for mass 5kg, a will be upward, ●T - 5g = 5a ------ 2 ☆☆adding 1 and 2, ●10g - 5g = 15a ●​5g = 15a ●a= g/3     Second one⬇️⬇️⬇️⬇️  ●●Initial speed=10m/s,  ●●Final speed=0  >>mue*g=•5×10=5m/s^2   ⭐⭐Applying third equation,,We get distance as 10 m  @skb

Answer 2

$\bold{Hello}$



Q.9) => This is an easy question. We have to take out acceleration and we know that acceleration is equal to => F/m .

Here , m is the total mass , m = m1 + m2

m1 = 5 Kg
m2 = 10Kg

total mass = 15 Kg .

Now force will be = ( m2 - m1)*g


→ Acceleration = F/m

→ $\bold{\frac{(m2-m1)g}{(m1+m2)}}$


→ (10-5)g / ( 5 + 10)


Acceleration :-» g/3 .



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Q.10) => Given in the question :-

» Mass of cylinder = 10 Kg
» velocity ( initial ) = 10 m/sec
» coefficient of friction = 0.5


→ Kinetic energy of cylinder :

→ 1/2 mv^2 => 500

Work done by cylinder = force*distance.

→ $\bold{\mu mg * s = Work done}$


→ 0.5 * 10 * 10 * s = 500


→ 50 s = 500


Distance = 10 m








Hope It Helps You. ^_^