Question

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Again Present Here With A Physics's problem

❔ An average depth of Indian Ocean is about 3000 m . Calculate the fractional compression ∆v /v of water at the bottom of the ocean , given that the bulk modules of water is
2.2 × 10 N/m^2 and g = 10m/s^2

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Answer 1

We know one thing

P = P₀ + ρgh

Where P₀ is the atmospheric pressure , g is acceleration due to gravity, h is the height from the Earth surface and ρ is density of water

Here, P₀ = 10⁵ N/m² , g = 10m/s² , h = 3000m and ρ = 10³ Kg/m³

Now, P = 10⁵ + 10³ × 10 × 3000 = 3.01 × 10⁷ N/m²

Again, we have to use formula,

B = P/{-∆V/V}

Here, B is bulk modulus and { -∆V/V} is the fractional compression

So, -∆V/V = P/B

Put , P = 3.01 × 10⁷ N/m² and B= 2.2 × 10⁹ N/m²

∴ fractional compression = 3.01 × 10⁷/2.2 × 10⁹ = 1.368 × 10⁻²

Answer 2

$\huge{\bf{\mathfrak{Answer :}}}$

We know one thing

P = P₀ + ρgh

Where P₀ is the atmospheric pressure , g is acceleration due to gravity, h is the height from the Earth surface and ρ is density of water.

Here,

P₀ = 10⁵ N/m² ,
g = 10m/s² ,
h = 3000m
ρ = 10³ Kg/m³

Now,

P = 10⁵ + 10³ × 10 × 3000
P = 3.01 × 10⁷ N/m²

Again, we have to use formula,

B = P/{-∆V/V}

Here, B is bulk modulus and { -∆V/V} is the fractional compression

So, -∆V/V = P/B

Put , P = 3.01 × 10⁷ N/m² and B= 2.2 × 10⁹ N/m²

∴ fractional compression = 3.01 × 10⁷/2.2 × 10⁹

= 1.368 × 10⁻²

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