Question

hello everyone
lion is back with his question

Answer 1

I got only 1 answer brother and it was 2.723 kg sq.m

Answer 2

# According to question we have to find moment of inertia.

Formula of moment of inertia ( l ) = mr²

1. Moment of inertia of system about the axis passing through the 0 cm marks.

We have given,

m1 = 3 kg

m2 = 5 kg

r1 = 30 cm = 0.3 m

r2 = 70 cm = 0.7 m

Now,

l1 = m1 ( r1 )²+ m2 ( r2 )²

= 3 (0.3)² + 5 (0.7)²

= 3 (0.09) + 7 (0.49)

= 0.27 + 2.46

= 2.72 kg m²

2. Moment of inertia of system about the axis passing through the 100 cm marks.

m1 = 3 kg

m2 = 5 kg

r1 = 100 - 30 = 70 cm

r1 = 70 cm = 0.7 m

r2 = 100 - 70 = 30 cm = 0.3 m

l2 = m1 (r1)² + m2 (r2)²

= 3 (0.7)² + 5 (0.3)²

= 3 (0.49) + 5 (0.09)

= 1.47 + 0.45

= 1.92 kg m²