Math, asked by kandikasammaiah, 7 months ago

hello frds can u (2x- 3/2y) ^3
do this problem ​

Answers

Answered by mrinaliparida7
0

Answer:

(2x-3/2y) ^3

=( 2*x-3/2*y)^3

= 2 in the numerator and denominator get canceled

= (x-3/y)^3

= According to the law of exponent, (a/b)^m= a^m/b^m

= x^3-3^3/y^3

= x^3-27/y^3 is your final answer

Step-by-step explanation:

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