hello frds can u (2x- 3/2y) ^3
do this problem
Answers
Answered by
0
Answer:
(2x-3/2y) ^3
=( 2*x-3/2*y)^3
= 2 in the numerator and denominator get canceled
= (x-3/y)^3
= According to the law of exponent, (a/b)^m= a^m/b^m
= x^3-3^3/y^3
= x^3-27/y^3 is your final answer
Step-by-step explanation:
Similar questions