Math, asked by ActionRaja7, 1 year ago

HELLO FRIEND
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Maths , LINEAR EQUATION
bas solve it :
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Jai hind jai Bharat....

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Answers

Answered by AsifAhamed4
3

Man's age = 40
Sons's age = 14 
Let 
Number of years = x 
father will be = 40 + x
Son will be = 14 + x 
Twice the age of son after x years = father's age after x years
2(14+x)=40+x


28+2x=40+x
2x-x=40-28
x=12 

After 12 years father will be twice as old as his son. 
Check
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Man's age = 40 +12 = 52 (which is twice of 26)
Sons's age = 14 + 12 = 26

@Be brainly

Answered by siddhartharao77
3

Let the age of father will be twice as old as his son after 'x' years.

Age of man = 40 + x.

Age of Son = 14 + x.

Now,

= > 40 + x = 2(14 + x)

= > 40 + x = 28 + 2x

= > 40 - 28 = x

= > x = 12.

Now,

Age of man after 12 years = 40 + 12 = 52 years.

Age of man after 12 years = 14 + 12 = 26 years.

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Hope this helps!


siddhartharao77: Mark as brainliest it my answer helps!
ActionRaja7: done yaar
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