Hello friend's!!
Plz answer this...
For what values of m, the system of equations x+2y=5 and 3x+my=-15 has no solution??
MridulAhi:
sorry I don't know how to solve it
it's ok...I got the answer
Answers
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x+2y-5=0
3x+my+15=0
For no solution ,
(1/3) = (2/m) ≠ (-5/15)
m=6 and m≠-6
So , m=6
3x+my+15=0
For no solution ,
(1/3) = (2/m) ≠ (-5/15)
m=6 and m≠-6
So , m=6
Thank you soo much
Np✌
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