Question

hello friends...

Answer this question.

Answer 1

This is isoceles triangle where AB= AC . and angle ACB + 120 = 180( Straight line makes 180°)
angle ACB = 60 So, Angle ABC = 60
sum of all angle of triangle is 180°
Angle A + Angle B + Angle C = 180
Angle A + 60° + 60° = 180°
Angle A = 60°

Answer 2

hu» Given

=> In ΔABC , AB = AC

________

Let's

=> angle(ABC) = b
=> angle(ACB) = c
________

then

=> angle(ABC) = angle(ACB)__ [ angles opp. to equal sides of a Δ are equal ]

________

» We know that :-

=> angle(ACB) + 120 = 180 [ liner pair ]

then

=> angle(ACB) = 60

thus

=> angle(ABC) = 60
______

» and we also know that.

» Sum off a triangle = 180

then

=> angle(A) + angle(B) + angle(C) = 180

=> angle(A) + 60 + 60 = 180

=> angle(A) = 180-120

=> angle(A) = 60
-_____________[ANSWER]

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