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$\mathsf { {sec}^{2}\pi \: + \: 2 .{sin}^{2} {\dfrac{3\pi}{2}} - {tan}^{2}{ \dfrac{5\pi}{3}}}$

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Answer 1

Answer:

0

Step-by-step explanation:

Given Equation is sec²π + 2 sin²(3π/2) - tan²(5π/3)

= (1/cos²(π)) + 2 cos²(-π) - tan² (2π/3)

= 1 + 2 cos² (π) - (-√3)²

= 1 + 2(-1)² - 3

= 1 + 2 - 3

= 0

Hope this helps!

Answer 2

Answer:

0

Step-by-step explanation:

sec^2(π) + 2 sin^2(3π/2) - tan^2(5π/3)

(1) + 2 (-1)^2 - (-√3)^2

1 + 2 - 3

0