Question

Hello friends...

Answer this questions 25,26 and 27.

No useless answers

Answer 1

For question 26

To prove = AB = BE = CF

proof : BE and CF are medians of ⛛ ABC

IN ⛛ ADC AND ⛛ BEA

DC=EA (halves of equal sides)
/_ACD = /_ BAE (60° EACH)
AC=AB

. : ADC=BEA(SAS CONGRUENCE)
. : AD = BE ( CPCT)
Similarly, BE = CF
HENCE, AD = BE = CF

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Answer 2

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The answer of u r question is..✌️✌️

Ans:✍️✍️✍️✍️✍️✍️✍️✍️

To prove = AB =BE =CF

Proof = BE AND CF ARE MIDPOINT OF TRIANGLE ABC

IN TRIANGLE ADC AND TRIANGLE BEA

DC=EA

ACD=BAC

AC=AB

ADC=BEA

SIMILARLY,

BE = CF

HENCE

AD=BF=CF


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