Question

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$\sf\: the\: roots\:of\:2x^{2}+x+3=0\: are$

Answer: $\frac{-1+-i\sqrt{23}}{4}$

Answer 1

hey mate,
your answer is in the attachment....

thanks...
nice to help you ✌️✌️

Answer 2

Heyy Buddy

Here's your Answer

Quadratic Formula :-

$a {x}^{2} + bx + c = 0$

Here,

a = 2 , b= 1 and c = 3.

$d = \frac{ - b + \sqrt{ {b}^{2} - 4ac} }{2a} \\ \\ = > \frac{ -1 + \sqrt{ {1}^{2} - 4 \times 2 \times 3} }{2 \times 2} \\ \\ = > \frac{ - 1 + \sqrt{1 - 24} }{4} \\ \\ = > \frac{ - 1 + \sqrt{ - 23} }{4} \\ \\ = > \frac{ - 1 + \sqrt{23} }{4}$

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