✌✌ HELLO FRIENDS HERE IS MY QUESTION ✌✌
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Answered by
12
Heya!!
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According to a theorem ;
The ratio of area of a two similar triangles is equal to square of their corresponding sides.
Since triangle PQR similar to triangle ABC.
Hence area of PQR/ area of ABC = (QR/BC) ^2
= (3/1)^2
= 9/1
Hope it helps uh!!
----------------------------
According to a theorem ;
The ratio of area of a two similar triangles is equal to square of their corresponding sides.
Since triangle PQR similar to triangle ABC.
Hence area of PQR/ area of ABC = (QR/BC) ^2
= (3/1)^2
= 9/1
Hope it helps uh!!
sam287:
thank you very much
Answered by
4
NOTHING NICE MAN
CHECKS OVER STIPES
In triangle ABD & PQM
angle A = angle P
1/2 angle A = 1/2 angle P
angleBAD =angle QPM
angle B = angle Q
so triangle ABD sim.. to triangle PQM
so AB/PQ = AD/ PM (C.S OF SIMILAR TRIANGLE)
CHECKS OVER STIPES
In triangle ABD & PQM
angle A = angle P
1/2 angle A = 1/2 angle P
angleBAD =angle QPM
angle B = angle Q
so triangle ABD sim.. to triangle PQM
so AB/PQ = AD/ PM (C.S OF SIMILAR TRIANGLE)
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