Question

Hello friends ❤❤
I have question for all of uh !! ❤❤
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The triangular side wall of a flyover have been used for advertisement. this side of the walls are 122 m, 22m and 120 m (see figure). the advertisement yield an earning of ₹ 5000 per m^2 per year. A company hired one of its walls for 3 months. How much rent did it pay?
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Answer 1

HEYA
THERE'S THE SOLUTION ⬆
So, the rent to be paid is Rs.1,65,000

Answer 2

$\huge\mathfrak\fcolorbox{red}{aqua}{solution}$

$\underline{\bold{The \: sides \: of \: the \: triangular \: wall \: are}} \\ \underline{ \bold{122m \: 120m \: and \: 22m.}}$

$\underline{ \bold{Let \: a \: = 122m, \: b = \: 22m}} \\ \underline{ \bold{and \: c \: = 120.}}$

$\underline{ \bold{THEN,}}$

${\bold{ \red{s \: = \frac{a + b + c}{2} }}}$

$= \frac{122 + 22 + 120}{2} = \frac{264}{2}$

$\pink{ \bold{ = 132 \: m}}$

${ \bold{ \blue{∴ area \: of \: a \: triangular \: wall = \sqrt{s(s - a)(s - b)(s - c)} }}}$

$= \sqrt{132(132 - 122)(132 - 22)(132 - 120)}$

$= \sqrt{132 \times 10 \times 110 \times 12}$

$= \sqrt{11 \times 12 \times 10 \times 11 \times 10 \times 12}$

$= 11 \times 12 \times 10$

$\bold{ { \green{ = 1320 \: {m}^{2} }}}$

∴ $\underline{ \bold{rent \: to \: be \: paid = area \times rate \times time}}$

$= (1320 \times 5000 \times \frac{3}{12} )$

$= (110 \times 5000 \times 3)$

$\bold{ \pink{\pink= 1650000}}$
$\pink{ - - - - - - - - - - - - - - - - - - - - }$
$\mathfrak{{glad \: help \: uh}}$
$\mathfrak{it \: helps \: uh}$
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$\mathfrak{ \huge{ \red{@vaibhavhoax}}}$