HELLO FRIENDS,
I NEED SOME INTEGERS QUESTIONS.
BECAUSE TOMMOROW IS MY EXAM SOME PRACTISE QUESTIONS
OF MATHS PLEASE
Answers
Answer:
these are some of them
please markme as brainliest
Question 1.
Fill in the blanks using < or >.
(a) -3 …… -4
(b) 6 ……. -20
(c) -8 …… -2
(d) 5 …… -7
Solution:
(a) -3 > -4
(b) 6 > -20
(c) -8 < -2
(d) 5 > -7
Question 2.
Solve the following:
(i) (-8) × (-5) + (-6)
(ii) [(-6) × (-3)] + (-4)
(iii) (-10) × [(-13) + (-10)]
(iv) (-5) × [(-6) + 5]
Solution:
(i) (-8) × (-5) + (-6)
= (-) × (-) × [8 × 5] + (-6)
= 40 – 6
= 34
(ii) [(-6) × (-3)] + (-4)
= (-) × (-) × [6 × 3] + (-4)
= 18 – 4
= 14
(iii) (-10) × [(-13) + (-10)]
= (-10) × (-23)
= (-) × (-) × [10 × 23]
= 230
(iv) (-5) × [(-6) + 5]
= (-5) × (-1)
= (-) × (-) × 5 × 1
= 5
Question 3.
Starting from (-7) × 4, find (-7) × (-3)
Solution:
(-7) × 4 = -28
(-7) × 3 = -21 = [-28 + 7]
(-7) × 2 – -14 = [-21 + 7]
(-7) × 1 = -7 = [-14 + 7]
(-7) × 0 = 0 = [-7 + 7]
(-7) × (-1) = 7 = [0 + 7]
(-7) × (-2) = 14 = [7 + 7]
(-7) × (-3) = 21 = [14 + 7]
Question 4.
Using number line, find:
(i) 3 × (-5)
(ii) 8 × (-2)
Solution:
(i) 3 × (-5)
From the number line, we have
(-5) + (-5) + (-5) = 3 × (-5) = -15
(ii) 8 × (-2)
From the number line, we have
(-2) + (-2) + (-2) + (-2) + (-2) + (-2) + (-2) + (-2) = 8 × (-2) = -16
Question 5.
Write five pair of integers (m, n ) such that m ÷ n = -3. One of such pair is (-6, 2).
Solution:
(i) (-3, 1) = (-3) ÷ 1 = -3
(ii) (9, -3) = 9 ÷ (-3) = -3
(iii) (6, -2) = 6 ÷ (-2) = -3
(iv) (-24, 8) = (-24) ÷ 8 = -3
(v) (18, -6) = 18 ÷ (-6) = -3
Question 6.
Solve the following:
(i) (-15) × 8 + (-15) × 4
(ii) [32 + 2 × 17 + (-6)] ÷ 15
Solution:
(i) (-15) × 8 + (-15) × 4
= (-15) × [8 + 4]
= (-15) × 12
= -180
(ii) [32 + 2 × 17 + (-6)] ÷ 15
= [32 + 34 – 6] ÷ 15
= [66 – 6] ÷ 15
= 60 ÷ 15
= 4
Question 7.
The sum of two integers is 116. If one of them is -79, find the other integers.
Solution:
Sum of two integers = 116
One integer = -79
Other integer = Sum of integer – One of integer = 116 – (-79) = 116 + 79 = 195
Question 8.
If a = -35, b = 10 cm and c = -5, verify that:
(i) a + (b + c) = (a + b) + c
(ii) a × (b + c) = a × b + a × c
Solution:
(i) Given that a = -35, b = 10, c = -5
LHS = a + (b + c) = (-35) + [10 + (-5)] = (-35) + 5 = -30
RHS = (a + b) + c = [(-35) + 10] + (-5) = (-25) + (-5) = -(25 + 5) = -30
LHS = RHS
Hence, verified.
(ii) a × (b + c) = a × b + a × c
LHS = a × (b + c) = (-35) × [10 + (-5)] = (-35) × 5 = -175
RHS = a × b + a × c = (-35) × 10 + (-35) × (-5) = -350 + (-) × (-) × (35 × 5) = -350 + 175 = -175
LHS = RHS
Hence, verified.
Question 9.
Write down a pair of integers whose
(i) sum is -5
(ii) difference is -7
(iii) difference is -1
(iv) sum is 0
Solution:
(i) (-2) + (-3) = -5
Hence, the required pair of integers = (-2, -3)
(ii) -10 – (-3) = -10 + 3 = -7
Hence, the required pair of integers = (-10, -3)
(iii) (-3) – (-2) = -1
Hence, the required pair of integers = (-3, -2)
(iv) (-4) + (4) = 0
Hence, the required pair of integers = (-4, 4)