Question

Hello FRIENDS PLS SOLVE THIS AND GET 20 POINTS..

IF k^2-3k+1=0,Then

k+1/k=??​

Answer 1

Step-by-step explanation:

$k {}^{2} - 3k + 1 = 0 \\ k {}^{2} + 1 = 3k \\ \frac{k {}^{2} }{k} + \frac{1}{k} = \frac{3k}{k} \\ k + \frac{1}{k} =3$

please mark it as brainliest answer...

Answer 2

Answer:

3

Step-by-step explanation:

k^2-3k+1=0

=>k^2 +1=3k

dividing k both sides

=>k^2/k+1/k=3k/k

=>k+1/k=3

plzz mark my answer as brainlist....