❤Hello Friends ❤
Question :
The distance between two stations is 425 kilometre two trains start simultaneously from these stations on parallel tracks to cross each other the speed of one of train is greater than that of the Other by 5 km per hour if the distance between of the two trains after 3 hours of their start is 20 kilometre find the speed of each train.
❤ Thanks ❤
❤ Sam ❤
Answers
Hi there !
_________________________
Solution :
Let the speed of one train be x km / h.
Then,
the speed of the other train = ( x + 5 ) km / h.
The distance travelled by the first train in 3 hours = 3x km.
The distance travelled by the other train in 3 hours = 3 ( x + 5 ) km.
.·. 425 - [ 3x + 3 ( x + 5 )] = 20
=> 425 - 3x - 3x - 15 = 20
=> 425 - 6x - 15 = 20
=> 410 - 6x = 20
=> 6x = 390
=> x = 390 / 6
=> x = 65
So,
The speed of the first train = 65 km / h.
Speed of the second train = ( 65 + 5 ) = 70 km/h.
________________________
Now, let's check the solution :
As obtained, the speed of the first train is 65 km/h and the speed of the second train is 70 km/h.
The distance travelled by the first train in 3 hours = (65 × 3) km = 195 km.
The distance travelled by the second train in 3 hours = (70 × 3) = 210 km.
The distance between the two trains after 3 hours
=> [425 - (195 + 210)] km
=> [425 - 405 ] km
=> 20 km
Which is same as given.
Hence, the speeds of the trains are 65 km/h and 70 km/h respectively.
______________________
Thanks for the question !
Let, the speed of train A (let) be x km/h
Then, speed of tran B (Let) = (x + 5) km/h
Distance traveled by train A in 3 hours is 3x
similarly Distance traveled by train B in 3 hours = 3(x + 5) km/h
ATQ,
=> 3(x+5) + 3x = 425 - 20
=> 3x + 15 + 3x = 405
=> 6x = 390
=> x = 65
Thus, speed of train A = 65 km/h
speed of train B = (65+5) = 70 km/h
______________
Amrit⭐