hello friends solve this!! plz
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2 756√10 agar Shai hai Tu photos send karo
The2mysteriious1soul:
plz
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Hey Mate !
Here is your solution :
1.
= [ -4^( 3/5 ) ] ÷ [ √16 - √25 ]
= [ -4^( 3/5 ) ] ÷ ( 4 - 5 )
= [ -4^( 3/5 ) ] ÷ ( -1 )
= 4^( 3/5 )
= ( 2^2 )^( 3/5 )
Using identity :
[ ( a^m )^n = a^( mn ) ]
= 2^{ 2 ( 3/5 ) }
= 2^( 6/5 )
= 2√2
2.
Q. Multiply 6√5 and 125√21.
= ( 6√5 × 125√21 )
= 125 × 6 √( 21 × 5 )
= 750√105
==================================
Hope it helps !! ^_^
Here is your solution :
1.
= [ -4^( 3/5 ) ] ÷ [ √16 - √25 ]
= [ -4^( 3/5 ) ] ÷ ( 4 - 5 )
= [ -4^( 3/5 ) ] ÷ ( -1 )
= 4^( 3/5 )
= ( 2^2 )^( 3/5 )
Using identity :
[ ( a^m )^n = a^( mn ) ]
= 2^{ 2 ( 3/5 ) }
= 2^( 6/5 )
= 2√2
2.
Q. Multiply 6√5 and 125√21.
= ( 6√5 × 125√21 )
= 125 × 6 √( 21 × 5 )
= 750√105
==================================
Hope it helps !! ^_^
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