Hello friends, solve this question. This question is asked in the amu diploma today.
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kiGiven
SOQ =120°
OQ = OS -(radii of circle)
Find - Angle RQS
In ∆SOQ,angle sum property
angle ( OSQ + QOS + OQS ) = 180°
IF OQ = OS
SO,OSQ = OQS = x -(Angles opposite to equal sides are equal )
@ x + x + 120 = 180
2x =180-120
x = 60/2
x = 30°
If OQR is perpendicular to RQT and RQT is a straight line
RQS = 90°-30°
SO RQS = 60°
I WISH IT HELP YOU|||
SOQ =120°
OQ = OS -(radii of circle)
Find - Angle RQS
In ∆SOQ,angle sum property
angle ( OSQ + QOS + OQS ) = 180°
IF OQ = OS
SO,OSQ = OQS = x -(Angles opposite to equal sides are equal )
@ x + x + 120 = 180
2x =180-120
x = 60/2
x = 30°
If OQR is perpendicular to RQT and RQT is a straight line
RQS = 90°-30°
SO RQS = 60°
I WISH IT HELP YOU|||
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