Question

hello frnd today question is How many terms of the sequence 18,16,14... should be taken so that their sum is zero?​

Answer 1

Step-by-step explanation:

Here a=18,d=−2.

Let there are n terms so that the sum is zero.

Now, S

n

=

2

n

[2a+(n−1)d]=0

⇒

2

n

[2×18+(n−1)×−2]=0

⇒36+(n−1)×−2=0

⇒n−1=18

⇒n=19

Therefore 19 terms of the sequence has to be taken so that their sum is zero.

I hope it will help you mark me brilliant and thanks me and don't forget to follow me

Answer 2

Answer:

Total 19 terms required

Step-by-step explanation:

I think this Q is related to AP

18,16,14,. ..

a= 18

d = 16-18 = -2

S(sum of n terms) = 0

n =. no of turn

S = n/2(2a + (n-1)d)

0 = [2×18 + (n-1)(-2)]

0 = 36 - 2n +2

0 = 38 -2n

n = 19