Question

hello frnds Gud mrng Pls ans this qus.​

Answer 1

option b)

hope it will help you

if seems than mark as branliest

Answer 2

Answer:

option B

Explanation:

Given : m_h= 1.67\times 10^{-27} \ kgm

h

=1.67×10

−27

kg

Net charge on hydrogen atom q = (e+\Delta e)-e = \Delta eq=(e+Δe)−e=Δe

Let the distance between them be dd.

Equating gravitational force and the electrostatic force, we get

\dfrac{Gm_h^2}{d^2} = \dfrac{k (\Delta e)^2}{d^2}

d

2

Gm

h

2

=

d

2

k(Δe)

2

Or \dfrac{(6.67\times 10^{-11})(1.67\times 10^{-27})^2}{d^2} = \dfrac{(9\times 10^9)(\Delta e)^2}{d^2}

d

2

(6.67×10

−11

)(1.67×10

−27

)

2

=

d

2

(9×10

9

)(Δe)

2

\implies \ \Delta e = 2.06\times 10^{-37} \ C⟹ Δe=2.06×10

−37

C

The correct answer is option B.