Question

hello guys answer this question of math step by step please ​

Answer 1

Answer:

By prime factorizing we have

6n = 2n x 3n

A number will end with 0 if it has at least 1 as the power of both 2 and 5 in its prime factorization. Since the power of 5 is 0 in the prime factorization of 6n we can conclude that for no value of n 6n will end with the digit 0.

Answer 2

Answer:

Let us take an example in which the number ends with 0.For eg:

10=5×2

100=2×5×5×2

In both these cases we can observe that number ending with 0 has 5 and 2 as their prime factors.

Whereas,

6^n=(2×3)^n

It has 2 as prime factor but it doesnot has 5. So it does not end with 0.

Then 6^n cannot end with zero for any natural number.