Question

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A man of mass 50kg starts moving on the earth and acquires a speed of 1.8m/s . with what speed does the earth recoil ? mass of earth = 6 × 10^34

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Answer 1

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ANSWER::

Mass of man , m₁ = 50 kg                 v₁ = 1.8 m/s
Mass of earth , m₂ = 6 x 10²⁴ kg        v₂ = ?

m₁v₁ = m₂v₂

50 x 1.8 = 6 x 10²⁴ x v₂

v₂ = (50 x 1.8) / (6 x 10²⁴) = 1.5 x 10⁻²³ m/s

Therefore , the earth will recoil at speed of 1.5 x 10⁻²³ m/s.

Hope it helps

Answer 2

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$\green{solution}$

Given :- mass of man = 50kg
speed = 1.8

Mass of earth = 6×10²⁴ kg

Since , According to conservation of mass of theorem .

m1V1 = m2V2

50×1.8 = 6× 10²⁴×V2

V2 = 50× 1.8/6×10²⁴

V2 = 1.5 × 10-²³ m /sec Answer ✔

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