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a*1³ - 3(a-1)*1 - 1 = 0
a - 3a + 3 - 1 = 0
-2a = -2
a = 1 Ans.
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Answer:1
Step-by-step explanation:Since 1 is a zera of the polynomial p(1)=0. So a*1^3-3(a-1)*1-1=0. Hence a-3a+3-1=0 . So 2a=2. Hence a=1.
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