Question

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Here is your question.....

Answer 1

SOLUTION –

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ɢɪᴠᴇɴ-

let r be the radius of cone and its slant height be l.
and
r1 be the radius of cylinder and h1 be the height.

sᴏ,

r= 2.5 cm ,
h= 6 cm,
r1= 1.5 cm,
h1= 20 cm.

ɴᴏᴡ,

$l = \sqrt{ {r}^{2} + {h}^{2} } \\ l = \sqrt{ {2.5}^{2} + {6}^{2} } \\ l = \sqrt{6.25 + 36} \\ l = \sqrt{42.25} \\ l = 6.5$
let S1 and S2 be the areas to be painted orange and yellow respectively.

S1 = curved surface area of the cone + base area of the cone - base area of the cylinder

–› S1 = πrl + πr^2 - πr1^2
–› S1 = π[ rl + r^2 - r1^2]
–› S1 = π[2.5×6.5 + (2.5)^2 - (1.5)^2] cm^2
–› S1 = 3.14( 16.25 + 6.25 - 2.25) cm^2
–› S1 = 3.14 × 20.25 cm^2
–› S1 = 63.585 cm^2...

ᴀɴᴅ,

S2 = curved surface area of the circle + area of the base of the cylinder
–› S2 = 2πr1h1 + πr1^2
–› S2 = πr1( 2h1 + r1 )
–› S2 = 3.14 × 1.5 ( 2×20+1.5) cm^2
–› S2 = 3.14 × 1.5 × 41.5 cm^2
–› S2 = 4.71 × 41.5 cm^2
–› S2 = 195.465 cm^2

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THANKS☺️

Answer 2

SOLUTION –

Given

let r be the radius of cone and its slant height be l.
and
r1 be the radius of cylinder and h1 be the height.

sᴏ,

r= 2.5 cm ,
h= 6 cm,
r1= 1.5 cm,
h1= 20 cm.

Now,

$l = \sqrt{ {r}^{2} + {h}^{2} } \\ l = \sqrt{ {2.5}^{2} + {6}^{2} } \\ l = \sqrt{6.25 + 36} \\ l = \sqrt{42.25} \\ l = 6.5$
let S1 and S2 be the areas to be painted orange and yellow respectively.

S1 = curved surface area of the cone + base area of the cone - base area of the cylinder

–› S1 = πrl + πr^2 - πr1^2
–› S1 = π[ rl + r^2 - r1^2]
–› S1 = π[2.5×6.5 + (2.5)^2 - (1.5)^2] cm^2
–› S1 = 3.14( 16.25 + 6.25 - 2.25) cm^2
–› S1 = 3.14 × 20.25 cm^2
–› S1 = 63.585 cm^2...

And,

S2 = curved surface area of the circle + area of the base of the cylinder
–› S2 = 2πr1h1 + πr1^2
–› S2 = πr1( 2h1 + r1 )
–› S2 = 3.14 × 1.5 ( 2×20+1.5) cm^2
–› S2 = 3.14 × 1.5 × 41.5 cm^2
–› S2 = 4.71 × 41.5 cm^2
–› S2 = 195.465 cm^2