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Here is your question
If the sum of first n terms of an AP is given by Sn = 3n2 +2n,
Find the nth term of the AP
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Answer:
Step-by-step explanation:
Let n= 1
Now S1 means a1
So, S1=3+2
=5
S2= 3*2*2+2*2
=12+4
=16
Now to get a2 you subtract a1 from S2
So, 16-5=11
So d= 6
So nth term of AP=
an=5+ (n-1)*6
= 5+6n-6
= 6n-1
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