Question

hello guys meh vikram 991

this question is very interesting

but logic is very hard.....

anybody solve this problem.....

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best answer only.....

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ki tum kitna smart Ho.....

Answer 1

in rectangle APRI :

angle RAI = 35 °

here angle PRA and Angle RAI are alternate angle .

thus , angle RAI = PRA = 35°

since , we know that measure of each angles of rectangle = 90°

since , Angle RAI = 35°

angle RAI + angle PAM = 90°

35° + angle PAM = 90°

angle PAM = 55°

angle ARI and Angle PAR are alternate angle

so Angle PAR = angle ARI = 55°

angle PAR = angle PAM = 55°

since, we know that the diagonals of rectangle intersects at common point at the centre of rectangle and the triangles formed inside the rectangle are isosceles.

and we know that the two sides and two angles of isosceles triangle are always equal.

in isosceles ∆ PMA :
------------------------------

angle PAM = angle APM = 55°

since ,we know that

sum of all the angles of isoceles triangle

= 180°

anglePAM + angleAPM + anglePMA = 180

55° + 55° + angle PMA = 180°

angle PMA = 180° - 110°

angle PMA = 70°

angle PMA and angle RMI are equal and opposite angles.

therefore , angle PMA = angle RMI = 70°

Answer:
------------
angleARI = 55° , angle RMI = 70°

and angle PMA = 70°
-------------------------------

Answer 2

Answer:

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Step-by-step explanation:

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