hello guys please help me by solving only one question please guys help me
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1
since
AB parallel to CD,
then
angle A + angle C =180°, (Sum of co-interior angle),
(3x+15)+(2x+45)=180°,
5x+60=180°,
5x=180°-60°,
then
5x=120°,
x=120°/5,
x=24°,
therefore
angle BAC=3×24+15=72°+15°=87°,
angle ACD=2×24+45=48°+45°=93°
AB parallel to CD,
then
angle A + angle C =180°, (Sum of co-interior angle),
(3x+15)+(2x+45)=180°,
5x+60=180°,
5x=180°-60°,
then
5x=120°,
x=120°/5,
x=24°,
therefore
angle BAC=3×24+15=72°+15°=87°,
angle ACD=2×24+45=48°+45°=93°
Answered by
3
Since AB is parallel to CD
sum of adjacent angles is 180°
A/Q 3x + 15 + 2x + 45 = 180
on solving this 5x = 120
x = 24°
angle BAC = 3 (24 ) + 15 = 72 + 15 = 87 °
angle ACD = 2 (24) + 45 = 48 + 45 = 93°
HOPE IT HELPS
IF YOU LIKE THE ANSWER
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sum of adjacent angles is 180°
A/Q 3x + 15 + 2x + 45 = 180
on solving this 5x = 120
x = 24°
angle BAC = 3 (24 ) + 15 = 72 + 15 = 87 °
angle ACD = 2 (24) + 45 = 48 + 45 = 93°
HOPE IT HELPS
IF YOU LIKE THE ANSWER
MARK AS BRAINLIEST. .☺
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