Hello guys please help me out..
Two resistors of 6 ohm and 3 ohm are connected in parallel . four such combination are connected in series. calculate the equivalent resistance thus formed.
Anonymous:
The answer should be 8 ohm
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FIRST RESISTORS ARE CONNECTED IN PARALLEL SO,
1/R' = 1/6 + 1/3
1/R' = 1/2
R' = 2 Ω
NOW FOUR SUCH CONNECTIONS ARE CONNECTED IN SERIES SO ,
R" = R' + R' + R' + R'
R" = 4R'
R" = 4 × 2
R" = 8 Ω
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