Question

hello guys! please help me to solve this​

Answer 1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

1.

$5 {x}^{2} - 3x - 2 = 0 \\ 5 {x}^{2} - 5x + 2x - 2 = 0 \\ 5x(x - 1) + 2(x - 1) = 0 \\ (5x + 2)(x - 1) = 0 \\ x = \frac{ - 2}{5} or \: x = 1$

2.

$3 {x}^{2} - 14x - 5 = 0 \\ 3 {x}^{2} - 15x + x - 5 = 0 \\ 3x(x - 5) + 1(x - 5) = 0 \\ (3x + 1)(x - 5) = 0 \\ x = \frac{ - 1}{3} or \: x = 5$

3.

$9 {x}^{2} - 3x - 2 = 0 \\ 9 {x}^{2} + 3x - 6x - 2 = 0 \\ 3x(3x + 1) - 2(3x + 1) = 0 \\ (3x - 2)(3x + 1) = 0 \\ x = \frac{2}{3} or \: x = \frac{ - 1}{3}$

4.

$48 {x}^{2} - 13x - 1 = 0 \\ 48 {x}^{2} - 16x + 3x - 1 = 0 \\ 16x(3x - 1) + 1(3x - 1) = 0 \\ (16x + 1)(3x - 1) = 0 \\ x = \frac{ - 1}{16} or \: x = \frac{1}{3}$

5.

${t}^{2} + 3t - 10 = 0 \\ {t}^{2} + 5t - 2t - 10 = 0 \\ t(t + 5) - 2(t + 5) = 0 \\ (t - 2)(t + 5) = 0 \\ t = 2 \: or \: t = - 5$

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