Question

☺☺hello guys please solve this☺

Find the distance between (0,√3) and ( √3 +1 , 1).☺

Answer 1

whole root over(0-(root3+1))squared+(root3-1)squared
=whole root over(0-3+1+3+1) (2root3gets canceled)
=whole root over(8)

Answer 2

By distance formula we can find out the distance between any two points.

Distance formula =
$\sqrt{(x2 - x1) {}^{2} + (y2 - y1) {}^{2} }$
Here,
putting √3 + 1 as x2, 0 as x1
1 as y2 and √3 as y1

So distance between (0, √3) and (√3 + 1, 1) =
$\sqrt{( \sqrt{3 } + 1 - 0) {}^{2} + (1 - \sqrt{3}) {}^{2} } \\ = > \sqrt{( \sqrt{3 } + 1 ) {}^{2} + (1 - \sqrt{3} ) {}^{2} } \\ = > \sqrt{3 + 1 + 2 \sqrt{3} + 3 + 1 - 2 \sqrt{3} } \\ = > \sqrt{4 + 4} \\ = > \sqrt{8}$
Hence, your answer is √8


Hope it helps dear friend ☺️✌️