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Answers
Solution
Let
∆PSR is Isosceles triangle because:-
PS = SR ( Given )
∠1 = ∠P .....1 ( Angle of opp. sides are equal )
Now take
∆SQR is Isosceles triangle because
SQ = SR ( Given )
∠2 = ∠Q ....2 ( Angle of opp. sides are equal )
Now
∆PQR
Using angle sum property of trigonometry we get
∠P + ∠Q + ∠R = 180⁰
From 1 and 2 we get
∠1 + ∠2 + ∠R = 180⁰ ∠R is ∠1 + ∠2 ( Given )
Now we get
∠1 + ∠2 + ∠1 + ∠2 = 180
2( ∠1 + ∠2 ) = 180
∠1 + ∠2 = 90⁰ ∠1 + ∠2 = ∠R
Now
∠R = 90⁰
Now Using pythagoras theorem
(Hypotenuse)² = ( Base )² + ( Perpendicular)²
Now we get
PQ² = QR² + PQ²
Hence proved
Step-by-step explanation:
Answer♡
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