Question

Hello guys !!

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Plz solve this.....

I will mark you as brainlist...


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Fltu ki bkwas skttt mna hai..​

Answer 1

Given: r1 = 1 cm, r2 = 2.5 cm, h = 6 cm

l = √h² + (r2-r1)²

= √(6)² + (2.5-1)² cm

= √36 + 2.25 cm

= √38.25 cm

= 6.18cm

So,

External Surface area = (curved surface area of frustum) + (curved surface area of hemisphere)

= 22/7(r1+r2)l +2.22/7.r1

= 22/7 [(1+2.5)6.18 + 2×(1)²] cm²

= 22/7 (3.5 × 6.18 +2) cm²

= 22/7 (21.63+2) cm²

= 22/7 × 23.63 cm²

= 519.86/7 cm²

= 74.26 cm²

plz mark as brainliest mate ^_^

Answer 2

I hope it will help you....