Question

Hello guys,
Question.

Construct the Rhombus:-BEND,in which BN=5.6cm and DE=6.5cm......

Please draw and send the answer........​

Answer 1

Answer:

hey dear❤~ur solution is

Given: BN = 5.6 cm, DE = 6.5 cm

To construct: A rhombus BEND.

Steps of construction:

(a) Draw DE = 6.5 cm.

(b) Draw perpendicular bisector of line segment DE.

(c) Draw two arcs of radius 2.8 cm from intersection point O, which intersects the line KN at B and N.

(d) Join BE, BD as well as ND and NE.

It is the required rhombus BEND.

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mark as brainliest❤

Answer 2

Step-by-step explanation:

sides will be BE=√{(5.6/2)^2+(6.5//2)^2}

=√{2.8*2.8+3.25*3.25)

=√{7.84+10.5625)

=√18.4025

=4.2898

Angles of rhombus are

DBE=2*tan inverse DO/OB

where O is centre of rhombus

BEN=2*tan inverse OB/BE