Hello guys,
Question.
Construct the Rhombus:-BEND,in which BN=5.6cm and DE=6.5cm......
Please draw and send the answer........
Answers
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Answer:
hey dear❤~ur solution is
Given: BN = 5.6 cm, DE = 6.5 cm
To construct: A rhombus BEND.
Steps of construction:
(a) Draw DE = 6.5 cm.
(b) Draw perpendicular bisector of line segment DE.
(c) Draw two arcs of radius 2.8 cm from intersection point O, which intersects the line KN at B and N.
(d) Join BE, BD as well as ND and NE.
It is the required rhombus BEND.
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Step-by-step explanation:
sides will be BE=√{(5.6/2)^2+(6.5//2)^2}
=√{2.8*2.8+3.25*3.25)
=√{7.84+10.5625)
=√18.4025
=4.2898
Angles of rhombus are
DBE=2*tan inverse DO/OB
where O is centre of rhombus
BEN=2*tan inverse OB/BE
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