Question

hello guys
write the answer​

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Amount=27104\:rupees}}}$

$\green{\tt{\therefore{Compound\:Interest=4704\:rupees}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given:}} \\ \tt: \implies Principal(p) = 16000 \: rupees \\ \\ \tt: \implies Time(t) = 3\:years \\ \\ \tt: \implies Rate\% = 20\% \\ \\ \red{\underline \bold{To \: Find:}} \\ \tt: \implies Comound \: Interest(C.I) = ?$

• According to given question :

$\tt \circ \:Principal = 16000 \: rupees \\ \\ \tt \circ \: Rate\% = 20\% \\ \\ \tt \circ \: Time = 2 \: years \\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies S.I= \frac{p \times r \times t}{100} \\ \\ \tt: \implies S.I = \frac{16000 \times 20 \times 2}{100} \\ \\ \green{\tt: \implies S.I = 6400 \: rupees} \\ \\ \bold{For \: Amount : } \\ \tt: \implies A =p + S.I\\ \\ \tt: \implies A = 16000 + 6400 \\ \\ \green{\tt: \implies A=22400 \: rupees }\\ \\ \tt \circ \: Principal = 22400 \\ \\ \tt \circ \: Rate\% = 20\% \\ \\ \tt \circ \: time = 1 \: year \\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies A=p(1 + \frac{ \frac{r}{2} }{100} )^{2t} \\ \\ \tt: \implies A = 22400 \times (1 + \frac{20}{2 \times 100} )^{2} \\ \\ \tt: \implies A= 22400\times 1.21\\ \\ \green{\tt: \implies A = 27104\: rupees} \\ \\ \bold{For \: Compound \: Interest : } \\ \tt: \implies C.I =A - p \\ \\ \tt: \implies C.I=27104 - 22400\\ \\ \green{\tt: \implies C.I= 4704\: rupees}$

Answer 2

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QUESTION :

3. A man brows borrowed Rs. 16000 for three years under the following terms.

20% Simple Interest for the first 2 years.

20% Compound Interest for the remaining 1 year on the amount due after 2 years , the interest being compounded half yearly.

SOLUTION :

Let us first Calculate the first Part.

We have the following information...

The initial Principle is Rs. 16000

Time is 2 years.

Rate is 20%

Type of Interest is Simple Interest compounded annually.

We know that,

SI = PTR / 100

Where :

P is the Principal

T is the time taken

R is the rate

So, Substituting the required values we get :

SI = 16000 × 2 × 20 / 100

=> SI = 160 × 40

=> SI = Rs. 6400

So, now the Principal for the third year Becomes :

Principle + SI

=> Rs. 16000 + Rs. 6400

=> Rs. 22400

Now, for Compound Interest, the principle is Rs. 22400

Rate is 20% Compounded Half Yearly.

Time is 1 year or two half years.

So,

We know that :

A = P × [ { 1 + { R / 2 } / 200 ] ^ 2n

=> A = 22400 × [ 1 1 / 100 ] ^ 2

Solving we get :

A = Rs. 27104

So Compound Interest

=> Amount - Principal

=> Rs. 27104 - Rs. 22400

=> Rs. 4704