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->clue is 12th class, physics-1st chapter
->11th question u solve enough
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option 4) F/16 is correct....
according to the condition
here
charges are Q/2 and the distance is 2R
therefore applying coloumbs law we get
F = K (Q/2) (Q/2) / (2R)^2
F = K (Q^2/4 ) / 4R^2
THERE FORE the force will be
F = K Q^2 / 16 R^2
that is F/16
according to the condition
here
charges are Q/2 and the distance is 2R
therefore applying coloumbs law we get
F = K (Q/2) (Q/2) / (2R)^2
F = K (Q^2/4 ) / 4R^2
THERE FORE the force will be
F = K Q^2 / 16 R^2
that is F/16
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1
HEYA...
Answr...
in the given attachment..
hope it's helpful..
Answr...
in the given attachment..
hope it's helpful..
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