Question

Hello I'm from Iran.but it isn't to country
چیکار کنم؟
$2x + 1 = \sqrt{11x - 2}$
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Answer 1

Answer:

yes what happened

Explanation:

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Answer 2

Answer:

x=1 or x= 2/3

Explanation:

$2x + 1 = \sqrt{11x - 2} \\ {(2x + 1)}^{2} = 11x - 2 \\ 4 {x}^{2} + 4x + 1 = 11x - 2 \\ 4 {x}^{2} - 7x + 3 = 0 \\ x = \frac{ - (b) \frac{ + }{ \: } \sqrt{ {b}^{2} - 4ac} }{2a} \\ a = 4 \: \: and \: b = ( - 7) \:and \: c =3 \\ x = \frac{ - ( - 7) \frac{ + }{ \: } \sqrt{ { (- 7)}^{2} - 4(4)(3)} }{2(4)} \\ x = \frac{ 7 \frac{ + }{ \: } \sqrt{ 49 - 48} }{8} \\ x = \frac{ 7 \frac{ + }{ \: } \sqrt{1} }{8} \\ x = \frac{ 7 \frac{ + }{ \: } 1 }{8} \\ x = \frac{7 + 1}{8} or \: x = \frac{7 - 1}{8} \\ x = 1 \: or \: x = \frac{3}{4}$

I hope you are clear if not just comment and don't forget to mark my answer as the brainliest.