Math, asked by iwillsu26, 5 months ago

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Answered by patilyogita848
1

Question 1

फर्स्ट क्वेश्चन का आंसर 3 ×64

ans 192

सेकंड का आंसर 64 * 12 आंसर 768

3) ans 1

4)ans1296 \times 128 \\ ans165888

5)1.07374182e9 \times 65536 \\  \:7.0368749e13

Answered by Anonymous
23

Simplify and apply the law of exponents:

1. 3 * 4³

4³ is nothing but 4 × 4 × 4 i.e, we need to multiply 4 three times, so multiplying 4 three times we get 4 × 4 × 4 = 64

➙ 3 * 64

192 Ans.

2. 4x³ * 2x³

Here we multiply 4 with the 2 and then add the powers of the variables

➙ ( 4 × 2 )⁽³ ⁺ ³⁾

8

512

3. -(9x)

Any number raise to power 0 is 1.

➙ - ( 1 )

-1

4. 6x⁴/2x⁷

Refer the attachment ( 1 ) . Here we will divide each term of the polynomial by the monomial and then simplify.

5. ( 4x⁵y/16xy⁴ )³

Refer the attachment ( 1 ).

Multiply the polynomials:

  • Multiply the numeral coefficients.
  • Multiply the literal coefficients.
  • Multiply results of steps 1 and 2.

1. 6y(2y + 3)

12y² + 18y

2. (2a -1) (8a - 5)

➙ 2a (8a - 5) -1 (8a - 5)

➙ 16a² - 10a - 8a + 5

16a² - 18a + 5

3. (4p - 1)²

use identity :- (a - b) = a² + b² - 2ab

➙ (4p)² + 1² - 2 × 1 × 4p

16p² + 1 - 8p

4. (2n + 2) (6n + 1)

➙ 2n (6n + 1) +2 (6n + 1)

➙ 12n² + 2n + 12n + 2

12n² + 14n + 2

5. (7x - 6) (5x + 6)

➙ 7x (5x + 6) -6 (5x + 6)

➙ 35x² + 42x - 30x - 36

35x² + 12x - 36

Divide the polynomial:

  • Division of monomial by another monomial = [Division of the numeral coefficients × Division of their literal coefficients]

1. - 9a³b²/3ab

3a²b

2. (18r⁵ + 36r⁴ + 27r³) ÷ 9r

  • Divide each term of the polynomial by the nominal and then simplify

➙ 18r⁵/9r + 36r⁴/9r + 27r³/9r

2r + 4r³ + 3r²

3. (9n³ + + 3n)/9n

Refer the attachment (2)

4. (30x³ + 2x² + 30x)/10r²

  • We can just factorise it and so the coefficients can be reduced to, and we already know that the variables are different ( unlike ) so we can not divide them.

2[(15x³ + x² + 15x)/5r²]

5. (m² - 7m - 11) ÷ (m-8)

Refer the attachment ( 3 )

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