Hello !!;
In a class of 10 students , there are 3 girls . in how many different ways all the students be arranged in rows such that no two of the three girls are consecutive ?
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Number of girls = 3 , number of boys = 7 . since there is no restriction on boys , therefore first of all arrange the 7 boys in 7! ways
×B ×B ×B ×B ×B ×B ×B ×
if the girls are arranged at the place ( includeding the two ends ) indicated by cross , no two of three girls will be consecutive .
now there are 8 places for 3 girls
•°• Required number = 8P3×7 ! = 8!/5!×7! = 4281 Answer ✔
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