Hello. In the underlined compound, it has been mentioned that there are 5 alpha hydrogen. Can someone explain me how?
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CH3-CH-CH2Br
The central carbon has the free radical and it is a secondary radical.
The two other carbons one on left and other on right - both are alpha carbons to the central carbon.
These two alpha carbons having hydrogen attached to them are called alpha hydrogens. The total number of alpha hydrogens = 3 +2 = 5
The central carbon has the free radical and it is a secondary radical.
The two other carbons one on left and other on right - both are alpha carbons to the central carbon.
These two alpha carbons having hydrogen attached to them are called alpha hydrogens. The total number of alpha hydrogens = 3 +2 = 5
nid16:
but bromine is attached to one of the carbon atoms. So why can't that carbon (to which br is attached) be the alpha carbon?
Be clear with your question.
You need the alpha hydrogen w.r.t bromine or w.r.t free radical carbon?
so.. if we con consider with respect to bromine then the no. of Alpha hydrogen will be 1 and if we consider with respect to free radical then the number of Alpha hydrogens will be 5
am i right?
Yes. Hope you are clear.
Yes. It's clear. Thank you so much. :)
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